How many carbon-hydrogen bond orbitals are av | vedclass

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(B) The ethyl carbocation is represented as $CH_3-CH_2^+ $.
In this structure,the positively charged carbon atom is $sp^2$ hybridized and possesses a

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The ethyl carbocation is represented as $CH_3-CH_2^+ $.
In this structure,the positively charged carbon atom is $sp^2$ hybridized and possesses a vacant $p$-orbital.
The adjacent carbon atom (the $\alpha$-carbon) is bonded to three hydrogen atoms.
Hyperconjugation occurs through the overlap of the $\sigma$-orbitals of the $C-H$ bonds with the vacant $p$-orbital of the adjacent carbocation.
Since there are $3$ $C-H$ bonds on the $\alpha$-carbon,there are $3$ such $C-H$ bond orbitals available for this overlap.
Therefore,the correct option is $B$.

How many carbon-hydrogen bond orbitals are available for overlap with the vacant $p$-orbital in ethyl carbocation?

Similar Questions

The correct stability order for the following carbocations is:

Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

Among the given cations,the most stable carbonium ion is

Rank the transition states that occur during the following reaction steps in order of increasing stability (least $\to$ most stable):
$1.$ $CH_3-O^+H_2 \to CH_3^+ + H_2O$
$2.$ $(CH_3)_3C-O^+H_2 \to (CH_3)_3C^+ + H_2O$
$3.$ $(CH_3)_2CH-O^+H_2 \to (CH_3)_2CH^+ + H_2O$

Arrange the $(C-H)$ bonds $x, y$ and $z$ in decreasing order of their bond dissociation energies in homolysis.

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